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Answer by Kpym for Calculations in TikZ for iterative procedure
As nobody mentioned the use of let, I add this answer for the seek for completeness.\begin{tikzpicture} \matrix[column sep=1cm]{ \node (n1) {1}; & \node (n2) {2}; & \node (n3) {3}; & \node...
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Answer by Alain Matthes for Calculations in TikZ for iterative procedure
It's possible to avoid the matrix \documentclass{article} \usepackage{tikz} \begin{document} \begin{tikzpicture} \node (n1) {1}; \foreach \x in {2,...,4} {% \node (n\x) at (\x-1,0) {\x}; \draw[red,...
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Answer by user4686 for Calculations in TikZ for iterative procedure
I think you just need expandable computations. Many things can be done with \numexpr. \documentclass{article}\usepackage{tikz}\begin{document}\thispagestyle{empty}\begin{tikzpicture} \matrix[column...
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Answer by user11232 for Calculations in TikZ for iterative procedure
Another version of evaluate:\documentclass{article}\usepackage{tikz}\begin{document}\begin{tikzpicture} \matrix[column sep=1cm]{ \node (n1) {1}; & \node (n2) {2}; & \node (n3) {3}; & \node...
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Answer by Peter Grill for Calculations in TikZ for iterative procedure
Yes it is possible, you just need to compute \x+1 first. One way to do that is to use \pgfmathtruncatemacro:Notes:I added arrows to make it clear that there were three iterations.As Paul Gaborit...
View ArticleCalculations in TikZ for iterative procedure
In many \foreach iterative procedures in TikZ I would like to relate the generic node called n\x -- where x is a natural number -- to another node the name of which is obtained by applying basic...
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